h=1+x-x^2/40

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Solution for h=1+x-x^2/40 equation: 


x in (-oo:+oo)

h = x-((x^2)/40)+1 // - x-((x^2)/40)+1

h+(x^2)/40-x-1 = 0

h+1/40*x^2-x-1 = 0

DELTA = (-1)^2-(1/40*4*(h-1))

DELTA = 1-1/10*(h-1)

1-1/10*(h-1) = 0

1-1/10*(h-1) = 0

11/10-1/10*h = 0

11/10-1/10*h = 0

11/10-1/10*h = 0 // - 11/10

-1/10*h = -11/10 // : -1/10

h = -11/10/(-1/10)

h = 11

DELTA = 0  <=>  t_1 = 11

x = 1/(1/40*2) i h = 11

x = 20 i h = 11

( x = ((1-1/10*(h-1))^(1/2)+1)/(1/40*2) or x = (1-(1-1/10*(h-1))^(1/2))/(1/40*2) ) i h > 11

( x = 20*((1-1/10*(h-1))^(1/2)+1) or x = 20*(1-(1-1/10*(h-1))^(1/2)) ) i h > 11

h-11 > 0

h-11 > 0 // + 11

h > 11

x in { 20, 20*((1-1/10*(h-1))^(1/2)+1), 20*(1-(1-1/10*(h-1))^(1/2)) }

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